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Hence, as angle of incidence is 55∘ angle of reflection too is 55∘ and the angle between the incident ray and the reflected ray is 55∘+55∘=110∘ .
= 25 degree. Since, the angle of incidence is equal to the angle of reflection, therefore the required angle of reflection = 25 degree.
Given: θi=32∘ θ i = 32 ∘ : angle of incidence. A. The angle of reflection can be calculated using the law of reflection. Therefore, the angle of reflection is θr=32∘ θ r = 32 ∘ .
The law of reflection states that light is reflected off of a surface, the angle of incidence is equal to the angle of reflection. therefore the angle of reflection is 29 degrees.
When a ray of light is incident normally on a plane mirror it means that the angle of incidence is 0ₒ. From the law of reflection, we find that angle of reflection is also 0. Thus, for normal incidence on a plane mirror, angle of incidence and angle of reflection are 0ₒ.
As the angle is increased to greater and greater angles, we would begin to observe less refraction and more reflection. That is, as the angle of incidence is increased, the brightness of the refracted ray decreases and the brightness of the reflected ray increases.
The angle of incidence (i) at which light is totally internally reflected is known as the critical angle. Explanation: The angle of incidence (i) at which light is totally internally reflected is known as the critical angle.
This normal incidence reflectivity is dependent upon the indices of refraction of the two media. For light from a medium of index n1 = normally incident upon a medium of index n2 = the reflectivity is. = %